In , Martínez-Avendaño and Zatarain-Vera  proved that hypercyclic coanalytic Toeplitz operators are subspace-hypercyclic under certain conditions. particular that the operator is universal in the sense of Glasner and Weiss) admits frequently hypercyclic vectors with irregularly visiting orbits. where is an operator with dense generalised kernel, must lie in the norm closure of the hypercyclic operators on, in fact in the closure of the.
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Post as a guest Name. Sign up using Email and Password. In other words, the smallest closed invariant subset containing x is the whole space. The proof seems correct to me.
Operators with hypercyclic Cesaro meansAll
There is no hypercyclic operator in finite-dimensional spaces, but the property of hypercyclicity in spaces of infinite dimension is not a rare phenomenon: Functional analysis Operator theory Invariant subspaces. Views Read Edit View history. In mathematicsespecially functional analysisa hypercyclic operator on a Banach space X is a bounded linear operator T: Such an x is then called hypercyclic vector.
Thank you I’ve changed it.
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I’m pretty new to this area of study so if there are logical lacune in my proof I’m sure there are many please let me know. This is material Operatorz self studying.